Question

From the given graph find the slope and area at point B.

Answer 1

i) Slope (m) = \(\frac{y_2\,-\,y_1}{x_2\,-\,x_1}\)

At B(16,40) ,Slope (m) = \(\frac{40\,-\,0}{16\,-\,0}= \frac{40}{16} =\,2.5\,m/s^2.\)

ii) Area = \(\frac{1}{2}\,\times\,16\,\times\,40=\,320\,m\)