Question

Calculate the wavelength of the first two lines of the Balmer series in the hydrogen spectrum.

Answer 1

Data : R = 1.097 x 10⁷ m^-1

For the Balmer series, n= 2.

For the first line (\(\lambda\)_Hα), m = 3.

\(\therefore\) The wavelength of the first Balmer line,

For the second line  (\(\lambda\)_Hβ) of the Balmer series, m = 4.

∴ The wavelength of the second Balmer line,

λ_Hβ = \(\cfrac{16}{3.291}\) x 10^-7 

= 4.862 × 10^-7 m = 4862 Å