Question

An observer of height 1.8 m is 13.2 m away from a palm tree. The angle of elevation of the top of the tree from his eyes is 45°. What is the height of the palm tree?

Answer 1

Height of the observer = 1.8 m 

Distance of the observer from the palm tree = 13.2 m

From the figure 

tan 45° = \(\frac{x}{13.2}\)

⇒ 1 = \(\frac{x}{13.2}\)

⇒ x = 13.2 m 

∴ Height of the palm tree = 13.2 + 1.8 = 15 m.