(i) (p2 + 5p + 4,) (p + 1)
p2 + 5p + 4 = p2 + p + 4p + 4
= p(p + 1) + 4(p + 1)
= (p + 1) (p + 4)
(p2 + 5p + 4) ÷ (p + 1)
= ((p+1)(p+4)) / (p+1) = p + 4
(ii) 15ab(a2 – 7a + 10) ÷ 3b(a – 2)
15ab (a2 – 7a + 10) ÷ 3b (a – 2)
15ab (a2 – 7a + 10) = 15ab (a2 – 5a – 2a + 10)
= 15ab [(a2 – 2a) – (5a -10)]
= 15ab [a(a – 2) – 5(a – 2)]
= 15ab(a – 2)(a – 5)
∴ 15ab (a2 – 7a + 10) ÷ 3b (a – 2)
