(i) 151m (2p2 – 2q2) ÷ 3l(p + q)
15lm (2p2 – 2q2) ÷ 3l (p + q)
15lm (2p2 – 2q2) = 15lm x 2(p2 – q2)
= 30lm (p + q) (p – q)
∴ 15lm(2p2 – 2q2) ÷ 3l(p + q)

(ii) 26z3(32z2 – 18) ÷ 13z2 (4z – 3)
26z3(32z2 – 18) ÷ 13z2 (4z – 3)
26z3(32z2 – 18) = 26z3 (2 x 16z2 – 2 x 9)
= 26z3 x 2 [16z3 – 9]
= 52z3 [(4z)3 – (3)3]
= 52z3 (4z + 3) (4z – 3)
∴ 26z3 (32z2 – 18) ÷ 13z2 (4z – 3)
