Correct option is (a) 2.7 N/mm
m = 35 kg
Total stiffness, sequi = 3s
N = 480 rpm
ω = \(\cfrac{2\pi\times480}{60}\)
= 50.2654 rad/s
ωn = \(\sqrt{\cfrac{s_{equi }}m}\) = \(\sqrt{\cfrac{3s}{35}}\) = rad/s
Here ξ = 0 (No damping)
FT = (10% of Fo)
= (0.1)Fo
\(\cfrac{F_r}{F_0}\) = 0.1 = ∈ ⇒ Transmissibility
\(\left(\cfrac{ω}{ω_n}\right)^2\) = 1 - 10 = - 9
(Not possible)
Taking (–ve)sign