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Prove that \( \sqrt{\frac{1+\sin \theta}{1-\sin \theta}}=\frac{\cos \theta}{1-\sin \theta} \)

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 \(\sqrt{\frac{1+sin\theta}{1-sin\theta}}=\sqrt{\frac{1+sin\theta}{1-sin\theta}\times\frac{1-sin\theta}{1-sin\theta}}\)

 = \(\sqrt{\frac{1-sin^2\theta}{(1-sin\theta)^2}}\) = \(\sqrt{\frac{cos^2\theta}{(1-sin\theta)^2}}\) = \(\frac{cos\theta}{1-sin\theta}\)

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