
hows the arrangement of the system.
Temperature of the source, T1 = 550 K
Temperature of the sink, T3 = 350 K
Intermediate temperature, T2 :
The efficiencies of the engines HE1 and HE2 are given by

Now from eqns. (iii) and (iv), we get
T1 – T2 = T2 – T3
2T2 = T1 + T3 = 550 + 350
∴ T2 = 450 K
Hence intermediate temperature = 450 K.