The minimm amount of `O_(2)(g)` consumed per gram of reactant is for the reaction :
(Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)
A. `C_(3)H_(8)(g) + 5 O_(2)(g) to 3 CO_(2)(g) + 4 H_(2)O(l)`
B. `P_(4)(s) + 5 O_(2)(g) to P_(4)O_(10)(s)`
C. `4 Fe(s) + O_(2)(g) to 2 FeO_(3)(s)`
D. `2 Mg(s) + O_(2)(g) to 2 MgO(s)`
