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Probability that a leap year selected at random will contain 53 Sundays is:  (A) 2 / 7  (B) 53 / 365 

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Probability that a leap year selected at random will contain 53 Sundays is: 

(A) 2 / 7 

(B) 53 / 365 

(C) 1 / 7 

(D) 7 / 365  

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1 Answer

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(A) 2 / 7

Total days 366 

n (E) = 2 n (S) = 7 

SM, MT, TW, WTh, ThF, F S, S S

p(E) = n(E) / n(S) = 2 / 7 

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