Question

The probability of a non leap year selected at random will contain 53 Sundays is

(A) \(\frac{1}{7}\)

(B) \(\frac{2}{53}\)

(C) \(\frac{1}{53}\)

(D) More than one of the above

(E) None of the above

Answer 1

The correct option is (A) \(\frac{1}{7}\)

A non-leap year has 365 days

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52 weeks = 52 x 7 = 364 days .

365– 364 = 1 day extra.

In a non-leap year there will be 52 Sundays and 1day will be left.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday, Saturday, Sunday.

Of these total 7 outcomes, the favourable outcomes are 1.

Hence the probability of getting 53 sundays = 1 / 7.