Question

In the diagram ABCD is a rectangle with AE = EF = FB, the ratio of the areas of triangle CEF and that of rectangle ABCD is 

(1) 1 : 6 

(2) 1 : 8 

(3) 1 : 9 

(4) 1 : 10

Answer 1

(1) 1 : 6

∴ Ar(CEF) = \(\frac{1}{3}\) Ar (ABC)

= \(\frac{1}{6}\) Ar (ABCD)

∴ \(\frac{Ar(CEF)}{Ar(ABCD)}=\frac{1}{6}\)