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A bag contains 4 white and 3 red balls. Two draws of one ball each are made without replacement. Then the probability that both the balls are red is

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A bag contains 4 white and 3 red balls. Two draws of one ball each are made without replacement. Then the probability that both the balls are red is

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Total number of balls = 4+3 = 7

Hence, the probability that both the balls are red = (3C1/7C1).(2C1/6C1)

=(3/7)(2/6)

= 1/7.

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