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निम्नलिखित समीकरण को हल कीजिए

(x2 – 3x + 3)2 – (x – 1)(x – 2) = 7

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दिया गया समीकरण

(x2 – 3x + 3)2 – (x – 1)(x – 2) = 7

(x2 – 3x + 2 + 1)2 – (x2 – 3x + 2) – 7 = 0 …(1)

समीकरण (1) में x2 – 3x + 2 = y रखने पर

(y + 1)2 – y – 7 = 0

y2 + 1 + 2y – y – 7 = 0

y2 + y – 6 = 0

y2 + 3y – 2y – 6 = 0

y(y + 3) – 2(y + 3) = 0

(y – 2)(y + 3) = 0

y = 2, – 3

जब y = 2 ⇒ x2 – 3x + 2 = 2

x2 – 3x = 0

x(x – 3) = 0

x= 0, 3

जब y = – 3 ⇒ x2 – 3x + 2 = – 3

x2 – 3x + 2 + 3 = 0

x2 – 3x + 5 = 0

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