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Sum of the cube of the roots of the equation x^4 - 3x^3 - 2x^2​​​​​​​ + 3x + 1 = 0 is equal to:

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Sum of the cube of the roots of the equation x4 - 3x3 - 2x2 + 3x + 1 = 0 is equal to:

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So required sum

= α3 + ß3 + \(\gamma^3\) + \(\delta^3\)

= 36 + 1 - 1 = 36 

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