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A chord of circle (2 - 2√2)^2 + (y - 2√2)^2 = r^2 is diameter of x^2 + y^2 - 2√2x - 6√2y + 14 = 0, then the value of r is

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A chord of circle (2 - 2√2)2 + (y - 2√2)2 = r2 is diameter of x2 + y2  - 2√2x - 6√2y + 14 = 0, then the value of r is

(1) √10

(2) √12

(3) √15

(4) √20

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Correct option is (1) √10

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