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If one of the diameters of the circle x^2 + y^2 - 2√2x - 6√2y + 14 = 0

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If one of the diameters of the circle x2 + y2 - 2√2x - 6√2y + 14 = 0 is a chord of the circle is a chord of the circle (x - 2√2)2 + (y - 2√2)2 = r2 , then the value of r2 is equal to 

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Correct answer is 10

PQ is diameter of circle

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