Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
250 views
in Mathematics by (59.9k points)
closed by

x2 + 2√2x – 6 = 0 मूल ज्ञात कीजिए।

1 Answer

+1 vote
by (62.1k points)
selected by
 
Best answer

दिए गए समीकरण x2 + 2√2x – 6 = 0 की तुलना व्यापक द्विघात समीकरण ax2 + bx + c = 0 से करने पर,

a = 1, b = 2√2, c = – 6

श्रीधराचार्य के सूत्र से,

यहाँ x = – √2 + 2√2 = √2

और x = – √2 – 2√2 = – 3√2

अतः समीकरण के दो अभीष्ट मूल x = √2 और x = – √32 हैं।

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...