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A nucleus of mass m disintegrate into two pieces of mass \(\frac m3\) and \(\frac{2m}3\). The ratios of their de-Broglie wavelength will be -

(1) \(\frac{\lambda_1}{\lambda_2} = \frac12\)

(2) \(\frac{\lambda_1}{\lambda_2} = \frac21\)

(3) \(\frac{\lambda_1}{\lambda_2} = \frac11\)

(4) \(\frac{\lambda_1}{\lambda_2} = \frac43\)

1 Answer

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Best answer

Correct option is (3) \(\frac{\lambda_1}{\lambda_2} = \frac11\)

Since their momentum will be same, so λdb =  same

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