Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
20.3k views
in Physics by (53.5k points)
closed by

A magnet hung at 45º with magnetic meridian makes an angle of 60º with the horizontal. The actual value of the angle of dip is 

(A) \(tan^{-1} \left(\sqrt{\frac 32}\right)\)

(B) \(tan^{-1}(\sqrt 6)\)

(C) \(tan^{-1} \left(\sqrt{\frac 23}\right)\)

(D) \(tan^{-1} \left(\sqrt{\frac 12}\right)\)

1 Answer

+1 vote
by (53.7k points)
selected by
 
Best answer

Correct option is (A) \(tan^{-1} \left(\sqrt{\frac 32}\right)\) 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...