In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed 'v' more than that of car B. Both the cars start from rest and travel with constant acceleration 1 a and 2 a respectively. Then 'v' is equal to:
(1) (a1 + a2)/2t
(2) √(2a1a2t)
(3) (2a1a2)/(a1 + a2)t
(4) √(a1a2t)
