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A gas is filled in a cylinder and its temperature is increased by 20% on Kelvin scale and volume is reduced by 10% keeping pressure constant. The percentage of the gas that will leak out is

(1) 15%

(2) 25%

(3) 40%

4) 30%

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(2) 25%

Let V and T denote initial volume and temperature of gas. The corresponding quantities finally are V1 , T1 . From Charle’s law V α  T (P remaining constant) therefore

V1 would have been the volume of gas if there was leakage in cylinder. However the final volume V´ = V - 0.1V = 0.9V.

∴ Percentage of volume leaked out = \(\frac{(1.2-0.9)V}{1.2V}\times100= 25\%\)

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