Question

A gas is filled in a cylinder, its temperature is increased by 20% on kelvin scale and volume is reduced by 10%. How much percentage of the gas will leak out 

(A) 15% 

(B) 25% 

(C) 40% 

(D) 30%

Answer 1

The correct option (B) 25%   

Explanation:

Let initial conditions = V, T

final conditions = V¹, T¹

by charge’s law, V ∝ T (P remains constant)

 (V/T) = (V¹/T¹)

∴ (V/T) = {V¹/(1.2T)}

 ∴ V¹ = 1.2V

As per question, volume is reduced by 10% i.e. V¹ = 0.9V so percentage  of volume leaked out = [{(1.2 – 0.9)V}/{1.2V}] × 100 = 25%