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A magnetic field, directed along z axis, varies as B = B0 x/a. where a is a positive constant. A square loop (of side l ), made of copper, is placed with its edges parallel to the x and y axes. If the loop is made to move with a constant velocity V0 , directed along x axis; the emf induced in it, would be

(1) B0 V0 \(\frac{l^2}{a}\)

(2) B0 V0 l

(3) B0 V0 \(\frac{l^2}{2a}\)

(4) B0 V0 \(\frac{l^3}{a^2}\)

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Best answer

(2) B0 V0 l

We have,

In one second the loop covers a distance of V0 , so that the final flux can be found by integrating dϕ between V0 and (V0 + l) .

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