Question

A straight rod PQ, of length L, is rotating about an axis passing through ‘O’ and perpendicular to its plane. The rod rotates in a uniform (and normal) magnetic field B, with an angular speed ω (The point ‘O’ is at a perpendicular distance L/3 from P). The potential difference between P and Q, would be the equal to

(1) \(\frac{BωL^2}{6}\)

(2) \(\frac{BωL^2}{4}\)

(3) \(\frac{BωL^2}{3}\)

(4) \(\frac{1}{2}BωL^2\)

Answer 1

 (1) \(\frac{BωL^2}{6}\)

The potential difference, between two ends of a rod, confined at one end, is given by 1/2 BωL²

(L = distance of the other end from the confined end)