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If P(x, y), F1(3, 0), F2(–3, 0) and 16x^2 + 25y^2 = 400, then PF1 + PF2 equals

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If P(x, y), F1(3, 0), F2(–3, 0) and 16x2 + 25y2 = 400, then PF1 + PF2 equals

(a) 8

(b) 6

(c) 10

(d) 12

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1 Answer

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by (51.4k points)

Correct option is (c) 10

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