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If P (x,y) be any point on 16x^2 + 25y^2 = 400 and F1(3,0), F2 (-3,0) are the foci, then PF1 + PF2

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If P (x,y) be any point on 16x2 + 25y2 = 400 and F1(3,0), F2 (-3,0) are the foci, then PF1 + PF2

(A)  8 

(B)  6 

(C)  10 

(D)  12

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1 Answer

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Best answer

Correct option  (C)  10

Explanation :

The given ellipse is

x2/25 + y2/16 = 1

In an ellipse, the sum of the focal distances of a point on the ellipse is equal to the length of the major axis. Hence

PF1 + PF = 2(5) = 10

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