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In a cuboid of dimension 2L x 2L x L , a charge q is placed at the centre of the surface ‘S’ having area of 4 L2 . The flux through the opposite surface to ‘S’ is given by

(1) \(\frac{q}{12ε_0}\) 

(2) \(\frac{q}{3ε_0}\)

(3) \(\frac{q}{2ε_0}\)

(4) \(\frac{q}{6ε_0}\)

1 Answer

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Best answer

Correct option is (4) \(\frac{q}{6ε_0}\)

Flux passing through shaded face = \(\frac{q}{6ε_0}\)

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