Question

The wave function (ψ) of 2s is given by 

ψ_2s = \(\frac{1}{2\sqrt{2\pi}}(\frac{1}{a_0})^{\frac{1}{2}}(2-\frac{r}{a_0})e^{-r/2a_0}\)

At r = r₀, radial node is formed. Thus, r₀ in terms of a₀

(1) r₀ = a₀

(2) r₀ = 4a₀

(3) \(r_0=\frac{a_0}{2}\)

(4) r₀ = 2a₀

Answer 1

(4) r₀ = 2a₀