Correct option is (1) 18.70 kg
The balanced equation is
No. of moles of NH3 formed = \(\frac{4\times10^3}{17}\)
∴ No. of moles of tollen’s reagent consumed \(=\frac{2\times10^3}{17}\)
So mass of tollen’s reagent = \(\frac{2\times10^3}{17}\times159\)
= 18.70 kg
