Given,
Vescope 1 = 1
Vescope 2 = 2
R1 = 1
R2 = 3
we know that
Vescope = \(\sqrt{2gR}\)
Vescope = \(\sqrt{gR}\)
\(\frac{V_{escope\,1}}{V_{escope\,2}}=\sqrt{\frac{g_1R_1}{g_2R_2}}\)
\(\frac{R_2}{R_1}(\frac{V_{escope\,1}}{V_{escope\,2}})^2=\frac{g_1}{g_2}\)
\(\frac{3}{1}\times(\frac{1}{2})^2=\frac{g_1}{g_2}\)
\(\frac{3}{4}=\frac{g_1}{g_2}\)
g1 = 3/4 g2