The length of a seconds pendulum at a height \( h=2 R \) from earth surface will be : (Given : \( R = \) Radius of earth and acc

The acceleration due to gravity at height 2R from the surface of the Earth will be,

The acceleration due to gravity at height 2R from the surface of the Earth will be

Length of the second's pendulum at the surface of the Earth is 1 m.

Since, time period of a pendulum is given by,

time period of a pendulum is given by

The length of a seconds pendulum at a height \( h=2 R \) from earth surface will be : (Given : \( R = \) Radius of earth and acceleration due to gravity at the surface of earth \( g=\pi^{2} ms ^{-2} \) )