Consider the centre of circle as O and triangle as ABC
OC = Radius of circle = r
OD = 4 – r
AD = 2 cm
AO = r

Therefore, in triangle AOD
(AO)2 = (AD)2 + (OD)2
r2 = 22 + (4 – r)2
r2 = 4 +16 – 8r + r2
8r = 20;
r = 20/8
= 5/2
= 2.5 cm
∴ Perimeter = 2π × r
= 2π × 2.5 cm
= 5π cm