To solve the quadratic equation 3x^2 - 18x + 6 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 3, b = -18, and c = 6.
Substituting these values into the formula, we get:
x = (-(-18) ± √((-18)^2 - 4 * 3 * 6)) / (2 * 3)
x = (18 ± √(324 - 72)) / 6
x = (18 ± √252) / 6
x = (18 ± √(36 * 7)) / 6
x = (18 ± 6√7) / 6
Simplifying further:
x = (3 ± √7)
So the solutions to the quadratic equation 3x^2 - 18x + 6 = 0 are x = (3 + √7) and x = (3 - √7).
