Let OAB be a given sector of a circle of radius r with are AB = l m and ∠AOB = θ radians.

Then,
2r + l = 20 m ....(1)
\(\frac{l}{r}=\theta\) ....(2)
Area \(\frac{1}{2}r^ 2\theta\) ....(3)
[Using (1), (2), (3)]

For maximum or minimum area
\(\frac{dA}{dr}=0 \) ⇒ 10 -2r = 0
r = 5
\(\frac{d^2A}{dr^2}=-2\) (negative) at r = 5
∴ A is maximum at r = 5m