Question

If 0.5 mol of BaCl₂ is mixed with 0-2 mol of Na₃PO₄, the maximum number of mole of Ba₃(PO₄)₂ that can be formed is

(a) 0.7

(b) 0.5

(c) 0.30

(d) 0.10

Answer 1

Correct option is (d) 0.10

3BaCl₂ + 2Na₃PO₄ → Ba₃(PO₄)₂ + 6 NaCl

Here Na₃PO₄ is limiting reagent.

Hence, moles of Ba₃(PO₄)₂ = \(\frac 12\) x 0.2 = 0.1