Question

If 0.50 mole of BaCl₂ is mixed with 0.20 mole of Na₃PO₄ , the maximum number of moles of  Ba₃(PO₄)₂ that can be formed is .

(a) 0.70

(b) 0.50

(c) 0.20

(d) 0.10

Answer 1

Correct option is (d) 0.10

Answer 2

Correct option is (d) 0.10

 \(3BaCl_2+2Na_3PO_4\longrightarrow Ba_3(PO_4)_2+6NaCl\)

 Number of moles of \(BaCl_2=0.50\) mole

Number of moles of \(Na_3PO_4=0.20\)

\(Na_3PO_4 \) is limiting reagent

\(\therefore\) Number of moles of \(Ba_3(PO_4)_2\) produce \(=\frac{0.20}{2}=0.10\) mol.