Correct option is (d) 0.10
\(3BaCl_2+2Na_3PO_4\longrightarrow Ba_3(PO_4)_2+6NaCl\)
Number of moles of \(BaCl_2=0.50\) mole
Number of moles of \(Na_3PO_4=0.20\)
\(Na_3PO_4 \) is limiting reagent
\(\therefore\) Number of moles of \(Ba_3(PO_4)_2\) produce \(=\frac{0.20}{2}=0.10\) mol.