Question

Hydrogen evolved at STP on complete reaction of 27 g of aluminium with excess of aqueous NaOH would be

(a) 22.4 l

(b) 44.8 l

(c) 67.2 l

(d) 33.6 l

Answer 1

Correct option is (d) 33.6 l

Al + 3NaOH → Na₃AIO₃ + \(\frac 32\)H₂

Volume of H₂(STP) formed from 27 g Al = \(\frac 32 \times \frac{22.4 \times 27}{27}\) = 33.6 l