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Oxidation number of iron in [Fe(H2O)5(NO)]SO4.

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Oxidation number of iron in [Fe(H2O)5(NO)]SO4.

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Let oxidation state of iron (Fe) be x.

[Fe(H2O)5(NO)+]2+

x + 0 + 0 = 2

x = 2

Hence, the oxidation state of iron in [Fe(H2O)5(NO)]SO4 is +2.

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