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In the reaction

\(MnO_4^- + SO_3^{2-} + H^+ \longrightarrow SO_4^{2 -} + Mn^{2 +} + H_2O\)

(a) \(MnO_4^-\) and \(H^+\) both are reduced

(b) \(MnO_4^-\) is reduced and \(H^+\) is oxidised

(c) \(MnO_4^-\) is reduced and \(SO_3^{2-}\) is oxidised

(d) \(MnO_4^-\) is oxidised and \(SO_3^{2-}\) is reduced

1 Answer

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Best answer

Correct option is (c) \(MnO_4^-\) is reduced and \(SO_3^{2-}\) is oxidised

Ox. No. of Mn decreases from +7 to +2 and that of sulphur increases from +4 in SO32- to +6 in SO42-.

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