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Evaluate: ∫∫∫e^x + y + zdzdydx. for z, y, x ∈ [(0, log2) (0, x) (0, (x + logy))

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Evaluate: ∫∫∫ex + y + zdzdydx. for z, y, x ∈ [(0, log2) (0, x) (0, (x + logy))

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= 8log2/3 - 28/9 + 1

Thus I = 8log2/3 - 19/9.

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