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रेखा \(\frac{x+1}{3}\) = \(\frac{y-1}{2}\) = \(\frac{z-1}{4}\) और समतल 2x + y – 3z + 4 = 0 के मध्य कोण ज्ञात कीजिए।

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समतल 2x + y – 3z + 4 = 0 के अभिलम्ब सदिश \(\overrightarrow{n}\) = 2i + j – 3k तथा रेखा

 \(\frac{x+1}{3}\) = \(\frac{y-1}{2}\) = \(\frac{z-2}{4}\) 

के समान्तर सदिश \(\overrightarrow{b}\) = 3i + 2j + 4k यदि समतल और सरल रेखा के बीच कोण θ हो तो

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