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+18 votes
970 views
in Olympiad by (25 points)
edited by

A small house is being heated by an electric heater of power P = 1 kW which maintains the interior temperature t1 = 19℃; the outside temperature t0 = 0℃. A man enters the house, upon which the room temperature starts rising and achieves a new value t2 = 20℃. Find the “heating power” of the man.

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1 Answer

+1 vote
by (30 points)
edited by

Initial condition

The heater power is maintaining the house at a constant temperature of 19°C.

This power compensates for the heat lost due to the temperature difference between the inside (19°C) and the outside (0°C).

After the man enters

The new equilibrium temperature is 20°C. Let's assume the heating power of the man is Pman

Since the heat loss is proportional to the temperature difference between the inside and outside, we can set up the following relationship:

Ptotal/Ttotal=Pinitialr/Tinitial

where:

Using the proportionality:

(Pheater+ Pman)/20 = (Pheater)/19

Run the equation with: 

Pheater = 1000W

we find that Pman= 52.63W

Thus, the heating power of the man is approximately 52.63 W

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