Question

A charged particle (m, q) stays in equilibrium in an electric field as shown

Then, value of q is

(1) \(\frac{mg}{2E}\)

(2) \(\frac{mg}{E}\)

(3) \(\frac{2mg}{E}\)

(4) \(\frac{mg}{4E}\)

Answer 1

Correct option is (2) \(\frac{mg}{E}\)

F_Net = 0

⇒ qE = mg

⇒ q = \(\frac{mg} E\)