Question

In Young’s double slit experiment, slits separation is 4 cm and separation between slit and screen is 1.5 m. A wave of wavelength 2 cm is incident of slits then find angular width of fringe.

(1) 0.75 rad

(2) 0.65 rad

(3) 0.80 rad

(4) 0.5 rad

Answer 1

Correct option is (4) 0.5 rad

Angular fringes width (\(\beta\)) = \(\frac \lambda d\)

\(= \frac{2 \times 10^{-2}}{4 \times 10^{-2}}\)

\(= 0.5 \) rad