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The number of solutions, of the equation \(\mathrm{e}^{\sin \mathrm{x}}-2 \mathrm{e}^{-\sin \mathrm{x}}=2\) is

(1) 2

(2) more than 2

(3) 1

(4) 0

1 Answer

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Best answer

Correct option is (4) 0

Take \(e^{\sin x}=t(t>0)\)

\(\Rightarrow \mathrm{t}-\frac{2}{\mathrm{t}}=2\)

\(\Rightarrow \frac{\mathrm{t}^{2}-2}{\mathrm{t}}=2\)

\(\Rightarrow \mathrm{t}^{2}-2 \mathrm{t}-2=0\)

\(\Rightarrow \mathrm{t}^{2}-2 \mathrm{t}+1=3\)

\(\Rightarrow(\mathrm{t}-1)^{2}=3\)

\(\Rightarrow \mathrm{t}=1 \pm \sqrt{3}\)

\(\Rightarrow \mathrm{t}=1 \pm 1.73\)

\(\Rightarrow \mathrm{t}=2.73 \text{ or }-0.73 \) (rejected as \(\mathrm{t}>0\))

\(\Rightarrow \mathrm{e}^{\sin \mathrm{x}}=2.73\)

\(\Rightarrow \log _{\mathrm{e}} \mathrm{e}^{\sin \mathrm{x}}=\log _{\mathrm{e}} 2.73\)

\(\Rightarrow \sin \mathrm{x}=\log _{\mathrm{e}} 2.73>1\)

So no solution.

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