Correct answer: 3

(I) x ≥ 0
x2 + 2x – 5x – 5 – 1 = 0
x2 – 3x – 6 = 0 → 1 root +ve
(II) –1 ≤ x < 0
–x2 – 2x – 5x – 5 – 1 = 0
x2 + 7x + 6 = 0 → x = –1 is a root
(III) –1 < x ≤ –2
x2 – 2x + 5x + 5 – 1 = 0
x2 – 3x – 4 = 0 → No root in given range
(IV) x < –2
x2 + 2x + 5x + 5 – 1 = 0
x2 + 7x + 4 = 0 → One root less than – 2
\(\therefore\) The number of distinct roots are 3.