The shortest distance between two lines x-3 / 2 = y+15 / -7 = z-9 / 5 and x+1 / 2 = y-1 / 1 = z-9 / 3 is

Question

The shortest distance between two lines \(\frac {x-3}{2} = \frac {y + 15}{-7} = \frac {z-9}{5}\) and \(\frac {x+1}{2} = \frac {y-1}{1} = \frac {z-9}{-3}\) is

(1) 4√3 

(2) 8√3 

(3) 6√3 

(4) 2√3

Answer 1

Correct option is (1) 4√3 

Shortest distance