Question

If mass of aniline taken is 9.3 g and produced mass of product is 26.4 g. Then calculate the percentage yield of reaction.

[Atomic mass of Br : 80 g mol^-1]

Answer 1

Correct answer: 80

Moles of aniline taken = \(\frac{9.3}{93}\) = 0.1 as molar mass of aniline is 93 g mol^-1

Molar mass = 330 g mol^-1

Yield = \(\frac{\text{Produced mass (real)}}{\text{Produced mass (ideal)}} \times 100\)

\(= \frac{26.4 \times 100}{330 \times 0.1}\)

\(= 80\)